Prova di Matematica 11 11 2023 Classe 3A

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In allegato le prove di assegnate il giorno 11 11 2023. Le ho inserite nel caso qualche studente desidera chiarimenti a riguardo.

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Prova 1

$1a)\hspace{2mm}k=\dfrac{16}{9}\hspace{3mm}1b)\hspace{2mm}k=\dfrac{2}{3}\hspace{3mm}1c)\hspace{2mm}k=\dfrac{9}{4}\hspace{3mm}$

$2a)\hspace{2mm}C\equiv(5,-1); D\equiv(2,-6)\hspace{3mm}2b)\hspace{2mm}4x+y-2=0 \hspace{3mm}2c)\hspace{2mm}2p=4\sqrt{34}$

$3a)\hspace{2mm}\overline{OH}=\dfrac{12}{5}\hspace{2mm}A_T=6\hspace{3mm}3c)I\equiv(-1,1)$

$4)\hspace{2mm}P\equiv(3,0)$ e $\overline{PH}=2\sqrt{5}$

$5)\hspace{2mm}3x-5y+10=0$



b]Prova 2[/b]

$1a)\hspace{2mm}k=-\dfrac{7}{2}\hspace{3mm}1b)\hspace{2mm}k=4\hspace{3mm}1c)\hspace{2mm}k=\dfrac{4}{9}\hspace{3mm}$

$2a)\hspace{2mm}C\equiv(4,0); D\equiv(2,-4)\hspace{3mm}2b)\hspace{2mm}3x+y-2=0 \hspace{3mm}2c)\hspace{2mm}2p=8\sqrt{5}$

$3a)\hspace{2mm}\overline{OH}=\dfrac{24}{5}\hspace{2mm}A_T=24\hspace{3mm}3c)I\equiv(2,-2)$

$4)\hspace{2mm}P\equiv(0,5)$ e $\overline{PH}=\dfrac{\sqrt{10}}{2}$

$5)\hspace{2mm}2x-3y-4=0$